## ints: Operators and Expressions

In this lesson you are going to have the opportunity to interact with operators +, -, *, and \ to get a specific value. The initial program has been Psuedo-Coded for you already so that you can interact directly with the correct Algorithm to begin with. For the Video I will doing a different scenario and Algorithm but it all directly applies to how you would solve the Assignment code to get the desired result. Good luck and enjoy... Believe it or not this is really not all that hard.

Hints:

The language used to derive the desired output is actually pretty simple. The language is called "Expressions" and they are as follows.

Increase: add one variable to another, its special symbol is +

a = 13 and b = 5

example a + b = k

Result k = 18

Decrease: subtract one variable by another, its special symbol is -

a = 13 and b = 5

example a - b = k

Result k = 8

Increment: add one to a variable, its special character is ++

a = 13 and b = 5

Example k = k ++

Result k = 14

Explanation the ++ operator simply adds one to the numeric value of k every time is called upon

Modulo: is simply the remainder in any division problem and its special character is %

Special note: by using the modulo you are telling the computer to divide and only pay attention to the reminder

a = 13 b = 5

Example k = a % b

In this step above we are dividing 13 by 5 and then only paying attention to the remainder which is 3

Result k = 3

Assign: is an operator that makes a variable something else, its special character is =

a = 13 b = 5

Example k = a

In this step the value of a (which is 13) is assigned to k (which now becomes 13)

Result k = 13

Hints:

The language used to derive the desired output is actually pretty simple. The language is called "Expressions" and they are as follows.

Increase: add one variable to another, its special symbol is +

a = 13 and b = 5

example a + b = k

Result k = 18

Decrease: subtract one variable by another, its special symbol is -

a = 13 and b = 5

example a - b = k

Result k = 8

Increment: add one to a variable, its special character is ++

a = 13 and b = 5

Example k = k ++

Result k = 14

Explanation the ++ operator simply adds one to the numeric value of k every time is called upon

Modulo: is simply the remainder in any division problem and its special character is %

Special note: by using the modulo you are telling the computer to divide and only pay attention to the reminder

a = 13 b = 5

Example k = a % b

In this step above we are dividing 13 by 5 and then only paying attention to the remainder which is 3

Result k = 3

Assign: is an operator that makes a variable something else, its special character is =

a = 13 b = 5

Example k = a

In this step the value of a (which is 13) is assigned to k (which now becomes 13)

Result k = 13

## The Assignment

So now that we have the basics and we have an idea of how to work with Incrementing, Decrecrementing, Assigning, Adding, Subtracting, Multiplying, and Dividing, what follows is the code and the Assignment that you get to tackle. Just take the info that you got and simply apply it.... You have got this!!!

## The Code

#include using namespace std;

int main(void)

{

int i, j, k;

cout << "Enter i: ";

cin >> i;

cout << "Enter j: ";

cin >> j;

// each of these lines below should be separate lines

// increase i by 2 giving k

// decrease j by i giving k

// divide i by j giving k

// increment k by 1 giving k

// modulo i divided j giving k

// increase k by k added to i giving k

// increase k by k divided by j giving k

// assign k times k times k to k giving k

// increase k by i times j giving k

cout << k;

return 0;

}

int main(void)

{

int i, j, k;

cout << "Enter i: ";

cin >> i;

cout << "Enter j: ";

cin >> j;

// each of these lines below should be separate lines

// increase i by 2 giving k

// decrease j by i giving k

// divide i by j giving k

// increment k by 1 giving k

// modulo i divided j giving k

// increase k by k added to i giving k

// increase k by k divided by j giving k

// assign k times k times k to k giving k

// increase k by i times j giving k

cout << k;

return 0;

}